12x^2-104x+105=0

Solution for 12x^2-104x+105=0 equation:

12x^2-104x+105=0

a = 12; b = -104; c = +105;
Δ = b2-4ac
Δ = -1042-4·12·105
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-76}{2*12}=\frac{28}{24}
=1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+76}{2*12}=\frac{180}{24}
=7+1/2
$